python - Does the enumerate() function count elements in advance? -

Python contains a function to support indexing on a collection. It provides index from the collection. In the

  item, calculation (list) for index: # start printing   
 In my case, I have a large list and wonder if Is it fast to use manually manually? Like  
  for items in the list = 0: # some print index index = index + 1    
 
 
  enumerate  function; This element is not counted as priority:  
  Fixed PyObject * enum_next (enumobject * en) {PyObject * next_index; PyObject * next_item; PyObject * Results = en- & gt; En_result; PyObject * This = N-> N_SIIT; Next_item = (* -> ob_type-> tp_iternext) (this); If (next_item == NULL) return tap; Next_index = PyInt_FromLong (N-> N_DEX); If (next_index == NULL) {Py_DECREF (next_item); Return tap; } N-> N_andex ++; If (result-> ob_refcnt == 1) {Py_INCREF (results); Py_DECREF (PyTuple_GET_ITEM (result, 0)); Py_DECREF (PyTuple_GET_ITEM (result, 1)); } And {result = PyTuple_New (2); If (result == faucet) {Py_DECREF (next_index); Py_DECREF (NEXT_ITEM); Return tap; }} PyTuple_SET_ITEM (result, 0, next_ index); PyTuple_SET_ITEM (results, 1, next_item); Return result; }   
 In this way, a flyover creates a  front   n  integer