MySQL: Order by absolute value of user-defined columns -

MySQL: Order by absolute value of user-defined columns -

There is a down-to-date version of a query attempting to use:

 < WHEE option_ id from the code> response to WHOE option_ id = 1 and poll_id = 1 and pref = 1) / (pref_percent from SELECT COUNT (*) responses as WHOE poll_id = 1 and pref = 1), (SELECT COUNT (*) responses = 1 and poll_id = 1) / (from replies to COUNT) * (WHEE poll_id = 1) as all_part, deviation through ABS (all_percent-pref_percent) responses by deviation as per order by the user DESC    I get this error:  Unknown column 'all_percent' in 'Field List'   
 Apparently, I have a user-defined column ( "All_percent") when creating another user defined column ("deviation").  
 So, my question is ... how can I modify this query to prevent this error?  
 i Instead of doing that task in PHP, it is actually to find sorted query results by deviation. Wrap an external query around your current question:   
 
  
  select user_id, pref_percent, all_percent, ABS Deviation (all_percent - pref_percent) as deviation (SELECT user_id, (WHEE option_ id = 1 and poll_id = 1 and pref = 1 from select COUNT (*) responses) / (SELECT COUNT (*) from responses WHERE poll_id = 1 and pref = 1) In the form of pref_percent, (WHERE option_ID = 1 and poll_id = 1) with select COUNT (*) responses) / (responses from replies) * (WHEE poll_id = 1) response to all user_id by the response of the group) Order by ORDER DESC    

 


  







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